Entry
Value
Name
RIGHT_EXISTS_AND_THM
Conclusion
!p q. (?x. p /\ q x) <=> p /\ (?x. q x)
Constructive Proof
Yes
Axiom
N|A
Classical Lemmas
N|A
Constructive Lemmas
T
T <=> (\p. p) = (\p. p)
(/\) = (\p q. (\f. f p q) = (\f. f T T))
(==>) = (\p q. p /\ q <=> p)
(!) = (\p. p = (\x. T))
(?) = (\p. !q. (!x. p x ==> q) ==> q)
Contained Package
bool-int
Comment
Standard HOL library retrieved from OpenTheory
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