Entry Value
Name RIGHT_AND_EXISTS_THM
Conclusion !p q. p /\ (?x. q x) <=> (?x. p /\ q x)
Constructive Proof Yes
Axiom 
N|A
Classical Lemmas N|A
Constructive Lemmas
  • T
  • T <=> (\p. p) = (\p. p)
  • (/\) = (\p q. (\f. f p q) = (\f. f T T))
  • (==>) = (\p q. p /\ q <=> p)
  • (!) = (\p. p = (\x. T))
  • (?) = (\p. !q. (!x. p x ==> q) ==> q)
    		•
    Contained Package bool-int
    Comment Standard HOL library retrieved from OpenTheory
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