Entry Value
Name foldr_cons
Conclusion !f b h t. foldr f b (CONS h t) = f h (foldr f b t)
Constructive Proof Yes
Axiom 
N|A
Classical Lemmas N|A
Constructive Lemmas
  • T
  • T <=> (\p. p) = (\p. p)
  • (/\) = (\p q. (\f. f p q) = (\f. f T T))
    		•
    Contained Package list-fold-def
    Comment Standard HOL library retrieved from OpenTheory
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