Entry Value
Name EQ_EXT
Conclusion !f g. (!x. f x = g x) ==> f = g
Constructive Proof Yes
Axiom 
(\a. a = (\b. (\c. c) = (\c. c))) (\d. (\e. d e) = d)
Classical Lemmas N|A
Constructive Lemmas
  • T
  • !x. x = x
  • !t. F ==> t <=> T
  • !t. T ==> t <=> t
  • !t. t ==> F <=> ~t
  • !t. t ==> T <=> T
  • !t. t ==> t
  • !t. (\x. t x) = t
  • F <=> (!p. p)
  • T <=> (\p. p) = (\p. p)
  • (~) = (\p. p ==> F)
  • (/\) = (\p q. (\f. f p q) = (\f. f T T))
  • (==>) = (\p q. p /\ q <=> p)
  • (!) = (\p. p = (\x. T))
    		•
    Contained Package bool-ext
    Comment Standard HOL library retrieved from OpenTheory
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